Beechmont Crest Home

Mathematics Home

 

 

 

MATHEMATICS

ALGEBRA

Solving Systems of Equations with the Addition Method 

 

Suppose you have are confronted with the following problem: 

Solve the system:  

 

x + y = 8

4x - 2y = 8

 

There are four steps involved in solving a problem like this:

 

  1. Multiply so that the coefficients of the x or of the y cancel out

  2. Add the equations

  3. Solve the equation derived from step 2.

  4. Substitute the answer from step into one of the original equations. Then solve for the remaining variable:

 

So, based on the above steps, the first thing I will do is multiply the first equation by 2:

 

2( x+y = 8)

 

2x + 2y = 16

 

Next I will add the two equations:

 

2x + 2y = 16

4x  - 2y =   8

 

Notice that the 2y and the -2y cancel each other out:

 

6x = 24

 

Divide both sides by 6 and we have:

 

x = 4

 

Now substitute the derived value for x back into one of the original equations. I will pick the first one because it is the simplest:

 

6 + y = 8

------

y = 8 - 6

y = 2

 

Therefore, the solution is: x = 6 and y = 2, or (6,2)